by Dalet Beht   Last Updated September 11, 2019 19:20 PM

for i = 1 to n do
for j = 1 to i do
for k = j to n do
a = a + 1


from algorithm above, i got the following triple summation:

$$\sum_{i=1}^n\sum_{j=1}^i\sum_{k=j}^n 1=?$$

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