So, I'm having quite some trouble understanding and solving the following exercise.
We are told that the following square signal (called Vin) is applied
Now, we are asked to find the voltage at A and B (i.e Va and Vb) at t1, t2, t3, and t4.
For t1, I understand the following. Since at t1 Vin makes a "jump", the capacitor becomes a short circuit and thus we ignore 2R.
For t2, we have a constant Vin, thus the capacitor has an infinite resistance (open circuit), and thus everything goes through 2R
For t3, it's similar to t1, but the "jump" is negative
For t4, since Vin = 0, Va = 0 and Vb = 0
Apart from t4, I don't know how I can use this analysis to find Va and Vb (assuming the analysis I've made is correct)
If you could help me or give me a hint, that would be nice, thank you.