Are the **likelihood** in Bayes Rule the same to the one in [Maximum likelihood estimation][1]?

by soplus2018   Last Updated October 10, 2019 02:19 AM

"Think Bayes by Allen B. Downey" calls the P(X | A) part likelihood in Bayes Rule

\begin{align} P( A | X ) = & \frac{ P(X | A) P(A) } {P(X) } \\\\[5pt] \end{align}

Are the likelihood here the same to the one in Maximum likelihood estimation?

Answers 1

Yes, the likelihood is the likelihood. You sometimes see likelihood defined only up to a multiplicative constant (as Fisher did) but that doesn't harm either of those applications if you are consistent in how you deal with it.

Unfortunately, by asking a yes-or-no question to which the answer is "yes" there's not much more to say. If the answer had been no, at least the difference would need to be explained.

October 10, 2019 01:49 AM

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